What is the result of ANDing the IP address 23.176.224.18 with the subnet mask 255.224.0.0?

To determine the result of ANDing the IP address 23.176.224.18 with the subnet mask 255.224.0.0, we need to perform a bitwise AND operation between the two values.

First, convert both the IP address and the subnet mask into binary format:

The IP address 23.176.224.18 in binary is:

• 23: 00010111

• 176: 10110000

• 224: 11100000

• 18: 00010010

Putting this together:

00010111.10110000.11100000.00010010

The subnet mask 255.224.0.0 in binary is:

• 255: 11111111

• 224: 11100000

• 0: 00000000

• 0: 00000000

Putting this together:

11111111.11100000.00000000.00000000

Now, perform the AND operation bit by bit:

1. The first octet:

00010111 (23)

AND 11111111 (255)

= 00010111 (23)

2. The second octet